Well guys, it’s time to take care of another misconception taken on by students learning astronomy for the first time. We know an orbit happens when we go fast enough around a body. We also know that when something is spinning, it flings things off of it (like the spinning playground thingy that everyone flies off of on home videos. Also, click here for a simple example). So the question is: do we feel less gravity at the equator because of the spinning of the Earth? If the Earth is spinning so fast, why don’t we get flung off? Let’s answer the first one:
*CAUTION PHYSICS AHEAD*
The force of gravity at the surface of the Earth equals (mass)*(acceleration due to gravity) (F=mg). The normal force (Fn) of the surface holds us up, and is actually what we feel. In other words, when an elevator accelerates up, we feel heavier because the normal force is higher to give us the acceleration of the elevator. Finally, the net acceleration of a body traveling in a circle is (velocity)^2/(distance to center).
The velocity of the equator is 465.1 m/s. That’s fast, right? Let’s do the calculation. By the way, the radius of Earth is 6378 km.
acceleration = m*v^2/r = m * (465.1)^2/(6378000) = 0.034 m/s^2
For comparison, the acceleration due to gravity is 9.8 m/s^2, almost 300 times as strong. So, if the Earth spun about 17 times faster, people would start to get flung off of the surface at the equator. For some perspective, a day would be about an hour and a half.
So when bodies are in space, assume that the rotation is negligible BEFORE you assume that the rotation might fling you. Odds are, for anything worth landing on, it won’t.